Time Limit: 3000MS Memory Limit: 65536K
Total Submissions: 12536 Accepted: 5529 DescriptionYou have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.
Input
Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.
OutputOutput is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".
Sample Inputdog ogday
cat atcaypig igpayfroot ootfrayloops oopslayatcay
ittenkayoopslay
Sample Outputcat
ehloopsHint
Huge input and output,scanf and printf are recommended.
SourceWaterloo local 2001.09.22
// POJ2503.cpp : Defines the entry point for the console application. // #include < iostream > using namespace std; struct Word{ Word():next( 0 ){} char from[ 12 ], to[ 12 ]; Word * next;};inline int calcKey( char word[], int SIZE){ int key = 0 ; int K = strlen(word); for ( int j = 0 ; j < K; ++ j) key = ((key << 2 ) + ((( int )word[j]) >> 4 )) ^ ((( int )word[j]) << 10 ); key = key % SIZE; key = key < 0 ? key + SIZE : key; return key;} int main( int argc, char * argv[]){ const int SIZE = 100003 ; Word hash[SIZE]; char w[ 25 ]; while (gets(w) && w[ 0 ] != 0 ) { Word * pw = new Word; sscanf(w, " %s %s " ,pw -> to,pw -> from); int key = calcKey(pw -> from, SIZE); Word * pt = & hash[key]; while (pt -> next != NULL) pt = pt -> next; pt -> next = pw; } while (gets(w) && w[ 0 ] != 0 ) { int key = calcKey(w, SIZE); Word * pt = & hash[key]; bool found = false ; while (pt -> next != NULL) { pt = pt -> next; if (strcmp(pt -> from, w) == 0 ) { found = true ; break ; } } if (found) printf( " %s\n " ,pt -> to); else printf( " eh\n " ); } return 0 ;}